If DIG is coded as 25 and CUT is coded as 49, then how will KICK be coded as ?

The below decoding question was asked in SSC CGL 2019 (Tier-1) exam held on 4th June, 2019, Shift-1, SET-1.

Q. If DIG is coded as 25 and CUT is coded as 49, then how will KICK be coded as ?

(a) 43    (b) 39    (c) 41    (d) 34

SOLUTION:

1) Give numbers to Alphabets from A to Z:

A=1, B=2, C=3, D=4, E=5, F=6, G=7, H=8, I=9, J=10, K=11, L=12, M=13, 

N=14, O=15, P=16, Q=17, R=18, S=19, T=20, U=21, V=22, W=23, X=24, Y=25, Z=26

2) Now write down number corresponding to the alphabet and add all the numbers as shown below.

On adding number for DIG and CUT, we can see they have difference of 5 from the actual result.

DIG:

• D + I + G = 4 + 9+ 7 = 20 

• Now add +5 ==> 20 + 5 = 25  

CUT:

• C + U + T = 3 + 21 +20 = 44

• Now add +5 ==> 44 + 5 = 49

3) To get the actual result, we need to add +5 after we have added numbers for KICK as shown below:

KICK:

• K + I + C + K = 11 + 9 + 3 + 11 = 34

• Now add +5 ==> 34 + 5 = 39

Answer is = 39

Hence, we can see that there are three things we need to do in such decoding questions:

a) Check if we can write numbers corresponding to the alphabet

b) Upon adding numbers for the alphabet, whether we are getting the expected result.

c) If not getting the expected result, what is the difference (+ or -) between the actual and expected result.